A stone is projected with a velocity of 29.4m/s at an elevation of 30° to the horizontal. calculate the time at which it will be at a height of 9.8m and also the horizontal distance from the point of projection corresponding to this height.
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Answer:
t=√2 and range=29.4√3/√2
Explanation:
t^2=(2h/g) =2
R=ucos t=√3/2 ×√2×29.4=29.4√3/√2
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