Question

A stone is projected with a velocity of 5m/s making an angle of 50 degrees with the vertical.
Calculate the range

Answer 1

Answer:

2.5 sin100 meter is the answer of this question

MARK as BRAINLIEST

Answer 2

GiveN :

• Velocity (u) = 5 m/s
• Angle (θ) = 50°

To FinD :

• Range

SolutioN :

Use formula for Range :

$\dashrightarrow {\boxed{\boxed{\tt{R \: = \: \dfrac{u^2 \sin 2 \theta}{g}}}}} \\ \\ \dashrightarrow \tt{R \: = \: \dfrac{5^2 \sin2(50^{\circ})}{9.8}} \\ \\ \dashrightarrow \tt{R \: = \: \dfrac{25 \: \times \: \sin 100^{\circ}}{9.8}} \\ \\ \dashrightarrow \tt{R \: = \: \dfrac{25 \: \times \: 0.98}{9.8}} \\ \\ \dashrightarrow \tt{R \: = \: \dfrac{24.5}{9.8}} \\ \\ \dashrightarrow \tt{R \: = \: 2.5} \\ \\ \underline{\sf{\therefore \: Horizontal \: Range \: is \: 2.5 \: m}}$

$\rule{150}{0.5}$

• Horizontal Range is the distance traveled by the body in horizontal plane.

• Maximum Height is the the maximum height reached by a projectile

• Max Height = u²Sin²θ/2g

• For maximum horizontal range angle should be of 45°. So, for the maximum distance in a projectile motion the angle should be 45°