A stone is projected with an initial velocity of 10m/s at an angle of 60° to the horizontal. The velocity of the stone at the height point is
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11th
Physics
Motion in a Plane
Projectile Motion
A particle is projected wit...
PHYSICS
A particle is projected with speed 10m/sat an angle 60 with horizontal. Then the time after which it's speed becomes half of the initial(g=10m/s^2)
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ANSWER
The initial speed is υ
0
=10. The horizontal component of velocity is
υ
0
cos60
0
=0.5υ
0
=5
At the highest point of the trajectory of the projectile, its speed is 5m/s which is half the initial speed.
The time taken to reach the maximum height (when the vertical component of the speed becomes 0) is
0=υ
0
cos60
0
=−gt
t=
10
10(
2
3
)
t=0.866sec
The required time is t=0.866 sec
Answer:
Vy at highest Point is Zero BUT V becomes purely Vx= 10cos60= 5 m/sec
Explanation:
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