Question

A stone is projected with speed of 50 m/'s at angle of 60 degree with the horizontal. the speed of the stone at highest point of trajectory is

Answer 1

Speed at highest point = uCosθ = 50*Cos60 = 50 * 1/2 = 25m/s

At highest point vertical component of velocity becomes zero. Hence speed at highest point is 25m/s

Answer 2

At the highest point of trajectory, a body has only horizontal component and no vertical component.
So the speed at the top is :
50cos 60 = 50x0.5= 25m/s