Question

A stone is projected with speed U and angle of projection is theta find radius of curvature at t is equal to zero

Answer 1

Answer:

The radius of curvature is $\dfrac{u^2\cos^2\theta}{g}$.

Explanation:

Given that,

Speed of stone = u

Angle = θ

The horizontal velocity is

$v = u\cos\theta$

U = speed of stone

We need to calculate the  radius of curvature at t = 0

Using centripetal force

$F_{c}=\dfrac{mv^2}{r}$

Where, F = force

m = mass of stone

v = speed of stone

put the value into the formula

$r=\dfrac{mu^2\cos^2\theta}{mg}$

$r=\dfrac{u^2\cos^2\theta}{g}$

Hence, The radius of curvature is $\dfrac{u^2\cos^2\theta}{g}$.