Physics, asked by ivallithanmay, 19 days ago

A stone is projected with the same velocity at 22 1/2°,67 1/2° to the horizontal. the ranges in the ratio of

Answers

Answered by anonymous625162
4

Answer:

The ratio shall be 1:1.

Pls do remember that, for two projectiles, having projectile angles as Theta and (90-theta) , have same range.

So if theta is 22.5, then 90-theta is 67.5

Hence both will have same range

hence range is in ratio 1:1.

Here is the reason why is it so-

Range of a projectile having theta as angle= (u^2 sin 2theta )/g

= (2 u^2 sin theta cos theta)/g

Range of a projectile having (90- theta) as angle = [u^2 sin 2(90-theta)]/g

= [u^2 2 sin (90-theta) cos (90-theta)]/g

= [u^2 2 cos theta sin theta]/g

as we can see now both the expressions r same, on simplifying

note: trigonometry laws are used in the proof. hope u r well versed with trigonometry

Pls make this answer the brainliest if understood :)

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