Question

A stone is projected with velocity souls
at an angle of 60 to the horizontal.
What will be the speed of the stone at
the time when it makes angle of 30 with the horizontal
​

Answer 1

Answer:

$Initially, \: </p><p>v \: vertical=vsinθ=vsin60∘=23v</p><p>v \: horizontal=constant \: =vcosθ=vcos60∘=21v</p><p></p><p>$

At the point of collision.

$</p><p>v \: horizontal=21v</p><p>v \: horizontal \: v \: vertical2=tan \: 30∘</p><p>i.e.</p><p>v \: vertical2=231v</p><p></p><p>$

Hence we have both the vertical velocities.

Using the equation of motion.

$v2−u2=2as</p><p>We \: get,</p><p>121v2−43v2=−2gh</p><p>128v2=2gh</p><p>v2=3gh</p><p></p><p>$

The speed of projection of the stone,

$v= \sqrt{} 3gh</p><p></p><p></p><p>$

Explanation:

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