Question

A stone is related from the top of the tower if the velocity is half of the height is 10meter sec ^1 then the hight of tower is take 10meter sec ^2​

Answer 1

Explanation:

A stone is dropped from the top of a tower.If it hits the ground after 10 seconds, what is the height of the tower?

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We can use the formula S=ut+( 1/2) a t2

Where u is initial velocity, ‘s’ is distance travelled (Height of the tower in this case), ‘t’ is time travelled and ‘a’ is the constant acceleration.

So , here as the object is dropped , the initial velocity ,u is 0

Acceleration is the acceleration due to gravity ‘g’ which is constant and has value of 9.8m/ s2

Time travelled is given as t=10 seconds

Substituting the values in the equation s=ut+( 1/2) a t2 we get

s=0 * 10 + ( 1/2) * 9.8 * 10 *10

s=490 meters

So, the height of the tower is 490 meters