Question

A stone is releasd from thr towerof height 19.6 m calculate its final velocity just before touching the ground

Answer 1

I think the best way to solve is
V sorry
${v }^{2} = {u }^{2} + 2gh$


If u=0 then

${v}^{2} = 2gh$
$g = 9.8$
$h = 19.6$
${v}^{2} = 2 \times 9.8 \times 19.6 = 384.16$
$v = \sqrt{384.16 } = 19.6$