Question

a stone is released from a height of 5m calculate its final velocity just before touching the ground take G is equal to 10 M per second square

Answer 1

Hi , there !!!

here is case of free fall


g = 10


h = 5m


this can be solved by using formula v = √ 2gh .

so , on putting the value we get

V = √ 2gh

=> V = √ 2× 10 × 5m

=> √ 10× 10

=> 10m / s


hope it helps you !!

thanks !!
Ranjan kumar

Answer 2

_/\_Hello mate__here is your answer--

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u = 0 m/s

v = ?

s = Height of the stone = 5 m

g = 10 ms−2

According to the equation of motion under gravity

v^2 − u^2 = 2gs

⇒ v^2 − 0^2 = 2 × 10 × 5

⇒ v^2 = 2 × 10 × 5 = 100

⇒ v = 10 ms−1

Hence, the velocity of the stone just before touching the ground is 10 ms^−1.

I hope, this will help you.☺

Thank you______❤

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