A stone is released from a tower n reaches the ground in 5s.how to find the height of the tower n velocity with which it will strike the ground
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v=u+at
v=10×5=50
v^2=u^2+2as
2500=2×10×s
s=125m
v=10×5=50
v^2=u^2+2as
2500=2×10×s
s=125m
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