a stone is released from rest and falls freely under gravity find speed of stone after 2s
Answers
Answered by
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initial velocity ,u = 0 (rest)
time taken ,t = 2s
acceleration due to gravity ,g = 10
First we have to find distance
2 equation of motion
s= ut + 1/2at^2
s = 0 × 2 + 1/2 × 10 ×2^2
s = 0 +20
s = 20
speed = distance / time
speed = 20 / 2
speed = 10 m/s
time taken ,t = 2s
acceleration due to gravity ,g = 10
First we have to find distance
2 equation of motion
s= ut + 1/2at^2
s = 0 × 2 + 1/2 × 10 ×2^2
s = 0 +20
s = 20
speed = distance / time
speed = 20 / 2
speed = 10 m/s
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Answered by
1
Question:
A stone is dropped from the edge of roof find the speed of the stone at 2 second after the stone was dropped.
Answer:
20 m/sec
Explained Answer:
Given:
Initial Velocity = 0m/s
Acceleration due to Gravity = 10m/s²
Time = 2s
Formula:
v = u + at
Here,
v = Final Velocity
u = Initial Velocity
a = Acceleration due to Gravity
t = Time
So, According to Question:
Asking:
Speed
v = u + at
v = 0 + 10 × 2
v = 20 m/sec
So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.
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