Physics, asked by simichuhi, 1 year ago

a stone is released from rest and falls freely under gravity find speed of stone after 2s

Answers

Answered by adi468
3
initial velocity ,u = 0 (rest)
time taken ,t = 2s
acceleration due to gravity ,g = 10

First we have to find distance
2 equation of motion
s= ut + 1/2at^2
s = 0 × 2 + 1/2 × 10 ×2^2
s = 0 +20
s = 20
speed = distance / time
speed = 20 / 2
speed = 10 m/s

adi468: plz mark me BRAINLIEST
Answered by Anonymous
1

Question:

A stone is dropped from the edge of roof find the speed of the stone at 2 second after the stone was dropped.

Answer:

20 m/sec

Explained Answer:

Given:

Initial Velocity = 0m/s

Acceleration due to Gravity = 10m/s²

Time = 2s

Formula:

v = u + at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration due to Gravity

t = Time

So, According to Question:

Asking:

Speed

v = u + at

v = 0 + 10 × 2

v = 20 m/sec

So, the speed of the stone at 2s after the stone was dropped is 20 m/sec.

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