Science, asked by deepanshukumarixd, 4 months ago

a stone is released from the haight of 19.5m find its velocity before touching the ground​

Answers

Answered by avenna
0

Answer:

Here, Initial velocity u=0

final velocity v=? (to be calculated )

Acceleration due to gravity g=9.8m/s2 (Stone comes down )

And Height h=19.6 m

Now ,we know that for a freely falling body :

v2=u2+2gh

So , v2=(0)2+2×9.8×19.6

v2=19.6×19.6

v2=(19.6)2

v=19.6 m/s

Thus the velocity of stone just before hitting the ground will be 19.6 metres per second .

Explanation:

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