a stone is released from the haight of 19.5m find its velocity before touching the ground
Answers
Answered by
0
Answer:
Here, Initial velocity u=0
final velocity v=? (to be calculated )
Acceleration due to gravity g=9.8m/s2 (Stone comes down )
And Height h=19.6 m
Now ,we know that for a freely falling body :
v2=u2+2gh
So , v2=(0)2+2×9.8×19.6
v2=19.6×19.6
v2=(19.6)2
v=19.6 m/s
Thus the velocity of stone just before hitting the ground will be 19.6 metres per second .
Explanation:
HOPE THIS MAY HELP YOU
Similar questions