A stone is released from the top of a tower 19.6m high. Calculate the initial velocity.
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since it starts from rest u=0 s=19.8 a= 9.8
v²-u²=2as
v²= 2*9.8*19.8= v=√388.08=19.69m/sec
v²-u²=2as
v²= 2*9.8*19.8= v=√388.08=19.69m/sec
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initial velocity u=0
because it is just dropped from the tower
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