Question

a stone is released from the top of a tower height 20m then its final than its final velocity just before touching the ground will be​

Answer 1

Answer:

inital velocity=0

final velocity=?

height =20m

using third equation of motion

v^2=u^2+2gs

v^2=0+2×10×20

v^2=400

v=20m/s

Answer 2

Given :

• u = 0
• g = 10 m/s²
• h = 20 m

To find :

• v = ?

Solution :

v² - u² = 2gh .......... ( formula )

=> v² - 0 = 2 x 10 x 20

=> v² = 2 x 10 x 20

=> v = √2 x 10 x 20

=> v = √20 x 20

=> v = √400

=> v = 20 m/s

Some other Formulas :

• Speed = d/t
• F = m. a
• a (bar) = v - v_0/t = Δv/Δt
• w = F x d
• P = W/Δt
• V = 1R
• PE = mgh
• p = mv