Question

A stone is released from the top of a tower.If its velocity at half of the height is 10 metre per second then height of the tower is (g=10 metre per second spauare

Answer 1

Answer:

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Answer 2

Concept Introduction: Motion in One Dimension is a basic part of Physics.

Given:

We have been Given:

$u = 0 \\ v = 10m {s}^{ - 1} \\ g = 10m {s}^{ - 2}$

To Find:

We have to Find: The Height of the Tower.

Solution:

According to the problem, we use the first equation to find the time,

$v = u + gt \\ 10 = 0 + 10 \times t \\ 10t = 10 \\ t = 1 \: sec$

Now putting it into second equation,

$h = ut + \frac{1}{2} g {t}^{2} \\ = 0 \times 1 + \frac{1}{2} \times 10 \times {1}^{2} \\ = 0 + \frac{10}{2} \\ h = 5m$

But this height is only half way path. So the full height of the tower is

$h = 2 \times 5m = 10m$

Final Answer: The height of the tower is

$10 \: m$

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