Question

a stone is released from the top of a tower of 20m then in final velocity just before touching the ground will be( take g=10 m/s2).​

Answer 1

Answer:

u=0

s=20m

${a = 10ms}^{ - 2}$

to find : v

${v}^{2} = {u}^{2} + 2as$

v^2= 2as. (u=0)

v^2= 2(10)(20)

v^2=400

v=20m/s