Question

A stone is released from the top of a tower of 9.6 meters high, before reaching the earth, determine its final velocity.

Answer 1

Using third equation of Motion
________________|

| v^2=u^2+ 2as
|________________|
v= ????

s=9.6

u=0

a=9.8m/s^2 (g)
___________________


v^2 =0 +2×9.8×9.6

v^2==== 188.16

v= √(188.16)

v= 13.71 m/sec

so final velocity of the stone is 13.71 m/sec^2


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