A stone is released from the top of a tower of 9.6 meters high, before reaching the earth, determine its final velocity.
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Using third equation of Motion
________________|
| v^2=u^2+ 2as
|________________|
v= ????
s=9.6
u=0
a=9.8m/s^2 (g)
___________________
v^2 =0 +2×9.8×9.6
v^2==== 188.16
v= √(188.16)
v= 13.71 m/sec
so final velocity of the stone is 13.71 m/sec^2
Happy New Year
________________|
| v^2=u^2+ 2as
|________________|
v= ????
s=9.6
u=0
a=9.8m/s^2 (g)
___________________
v^2 =0 +2×9.8×9.6
v^2==== 188.16
v= √(188.16)
v= 13.71 m/sec
so final velocity of the stone is 13.71 m/sec^2
Happy New Year
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