a stone is released from the top of a tower of height 19.6 m calculate the the final velocity just before touching the ground.
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19.6 m/s is the ans
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The final velocity of the stone just before touching the ground is 19.6m/s.
Step-by-step explanation:
Given:-
- Initial velocity of the stone (u) = 9.8m/s².
- Value of the Gravity (g) = 9.8m/s².
- Height of the tower (h) = 19.6m
Need to find:
- The final velocity of the stone just before touching the ground.
SOLUTION:-
As we know that,
v² = u²+2gh
Putting values in this formula,
We get;
v² = 0²+2(9.8×19.6)
v² = 19.6×19.6
v² = (19.6)²
v = 19.6 m/s
Hence,the final velocity of the stone just before touching the ground is 19.6 m/s.
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