Question

A stone is released from the top of a tower of
height 19.6 m. Its final velocity just before
touching the ground is​

Answer 1

Step-by-step explanation:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v

2

=u

2

+2gs

v

2

=0+2×9.8×19.6

v

2

=384.16

⇒v=19.6m/s