Question

A stone is released from the top of a tower of height 19.6 m. Then its final velocity just before touching the ground will be:​

Answer 1

Answer:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v 2 =u 2+2gs

v 2 =0+2×9.8×19.6

v 2 =384.16

⇒v=19.6m/s

here your answer