Question

A stone is released from the top of a tower of height 19.6 m. Then its final velocity just before touching the ground will be:

Answer 1

Answer:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v

2

=u

2

+2gs

v

2

=0+2×9.8×19.6

v

2

=384.16

⇒v=19.6m/s

Explanation:

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