Physics, asked by ritvikkr, 11 months ago

A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.​

Answers

Answered by gladson077
1

check the drawing.

ifitwas not clear reply

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Answered by vv1112004
2

Data:

u=0m/s

s= 19.6m

g=9.8m/sec²

v=?

2gs=v²-u²

2gs+u²=v²

2×9.8×19.6 + (0)² = v²

384.16=v²

√384.16=v

√38416/100=v

√196×196/10×10=v

196/10 =v

19.6 m/sec=v

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