A stone is released from the top of a tower of height 19.6m . then it's final velocity just before touching the ground will be
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Answer:
Initial Velocity u=0
Fianl velocity v=?
Height, s=19.6m
By third equation of motion
v
2
=u
2
+2gs
v
2
=0+2×9.8×19.6
v
2
=384.16
⇒v=19.6m/s
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