A stone is released from the top of a tower of height 19.6m. what is its final velocity just before reaching the ground
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Answer:
19.6ms-1
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Explanation:
s=h= 19.6m
u= 0m/s
a=g= 9.8m/s²
Third one
2as=v² - u²
2×9.8×19.6= v² - 0²
19.6×19.6 = v²
√19.6×19.6 = v
19.6 =v
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