Question

A stone is released from the top of a tower of height 19.6m, Calculate its final velocity just before touching the ground ?

Answer 1

v
$v ^{2} - u {}^{2} = 2gh$
v^2=0+2(9.8)19.6
v^2=19.6×19.6
v=19.6

Answer 2

s = + 19.6 m

u = 0

g = 9.8 ms^-2

v = ?

Using Equation of Gravitation

v^2 = u^2 + 2gs

v^2 = 0 + 2 × 9.8 × 19.6

v = 19.6 ms^-1