a stone is released from the top of a tower of height 19.6m. calculate its final velocity just before touching the ground............
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_/\_Hello mate__here is your answer--
u = 0 m/s
v = ?
s = Height of the stone = 19.6 m
g = 9.8 ms−2
According to the equation of motion under gravity
v^2−u^2=2gs
⇒ v^2−(0)^2=2×9.8×19.6
⇒ v^2=2×9.8 ×19.6=(19.6)^2
⇒ v=19.6 ms−1
Hence, the velocity of the stone just before touching the ground is 19.6 ms^−1.
I hope, this will help you.☺
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