Question

A Stone Is released from the top of a Tower of height 20 m then Its Final Velocity JusT before touching the ground will be (take g =10m/s)​

Answer 1

Answer:

200

Explanation:

20×10 = 200 m ÷s ..... understand follow me

Answer 2

Solution

GIVEN

A stone is release from the the top of a tower of height 20 m

TO DETERMINE

The final velocity just before touching the ground

CALCULATION

Initial Velocity = u = 0 m/s

Height = h = 20 metre

$\sf{ g\: = 10 \: \: m /{s}^{2} \: }$

We are aware of the equation that

$\sf{ {v}^{2} \: = {u}^{2} + 2gh \: }$

$\implies \: \sf{ {v}^{2} \: = {(0)}^{2} + 2 \times 10 \times 20 \: }$

$\implies \: \sf{ {v}^{2} \: = 400 }$

$\implies \: \sf{ {v}\: = \: 20}$

Hence the final velocity just before touching the ground is 20 m/s

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