Question

A stone is released from the top of a tower of height 20m Then its final velcoity just before touching the ground will be (Take g=10m/s`2)​

Answer 1

Given :

• u = 0

• g = 10 m/s²

• h = 20 m

To find :

• v = ?

Solution :

• v² - u² = 2gh .......... ( formula )

=> v² - 0 = 2 x 10 x 20

=> v² = 2 x 10 x 20

=> v = √2 x 10 x 20

=> v = √20 x 20

=> v = √400

=> v = 20 m/s

Some other Formulas :

• Speed = d/t

• F = m. a

• a (bar) = v - v_0/t = Δv/Δt

• w = F x d

• P = W/Δt

• V = 1R

• PE = mgh

• p = mv

Answer 2

Answer:

v=20

Explanation:

2gs=$v^{2}$-$u^{2}$

2*10*20=$v^{2} +u^{2}$

400=$v^{2} +o^{2}$

400=$v^{2}$

v=$\sqrt{400$

v=20

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