Question

A stone is released from the top of a tower of height 4.9 M calculate its final velocity before it touches the ground and time taken to reach the ground

Answer 1

Intial velocity(u)=0, displacement (s)=4.9m,Accelration due to gravity is equal to9.8ms^-2,Final velocity (v)=? g=9.8, g=a, v^2-u^2=2as, v^2-(0)^2=2(9.8)(4.9), v^2 =96.04ms^-1