Question

A stone is released from the top of a tower of height 45m. The final velocity of the stone just before touching the ground will be (take g = 10 m/s² )Required to answer. Single choice.
(1 Point)

30 m/s

196 m/s

60 m/s

40 m/s​

Answer it And explain your answer also

Answer 1

QuestioN :

A stone is released from the top of a tower of height 45m. The final velocity of the stone just before touching the ground will be (take g = 10 m/s² )Required to answer. Single choice.

30 m/s

196 m/s

60 m/s

40 m/s​

GiveN :

• Initial velocity ,u = 0m/s

• Height ,h = 45 m

• Acceleration due to gravity ,g = 10m/s²

To FiNd :

• Final Velocity before touching the ground,v

ANswer :

30 m/s

SolutioN :

As we have to calculate the Final velocity of ball before touching the ground.

Using 3rd Equation of Motion

• v² = u² +2gh

where,

• v denote final velocity
• u denote initial velocity
• g denote acceleration due to gravity
• h denote height

Substitute the value we get

→ v² = 0² + 2×10 × 45

→ v² = 0 + 20 × 45

→ v² = 900

→ v = √900

→ v = 30 m/s

∴Hence, the velocity of ball before touching the ground is 30 m/s.

Answer 2

Answer:

30 m/s

Step-by-step explanation:

→ v² = 0² + 2×10 × 45

→ v² = 0 + 20 × 45

→ v² = 900

→ v = √900

→ v = 30 m/s

∴Hence, Proved