Question

a stone is released from the top of a tower of height 490m its final velocity just before touching the ground is​

Answer 1

Answer:Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v  

2

=u  

2

+2gs

v  

2

=0+2×9.8×19.6

v  

2

=384.16

⇒v=19.6m/s

Explanation:

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Answer 2

Answer:

give time first then velocity will be found mark me brainliest I need only one more to become expert