Question

a stone is released from the top of a tower of height 9.6m calculate the final v​

Answer 1

Answer:

intial velocity u=0m/s

h=9.6m

v=√2gh

v=√2*9.8*9.6

=13.71m/s

Answer 2

Answer:

According to the equation of motion under gravity v2 − u2 = 2gs Where, u = Initial velocity of the stone = 0 m/s v = Final velocity of the stone s = Height of the stone = 19.6 m g = Acceleration due to gravity = 9.8 ms−2 ∴ v 2 − 02 = 2 × 9.8 × 19.6 ⇒ v 2 = 2 × 9.8 × 19.6 = (19.6)2 ⇒ v = 19.6 ms−1