Question

a stone is released from the top of a tower of height of 19.6cm calculate its final velocity just before touching the ground​

Answer 1

Answer:

solved

Explanation:

v = √2gh = √2×9.8 x19.6 = 19.6 ≈ 20 m/s

Answer 2

Answer:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v

2

=u

2

+2gs

v

2

=0+2×9.8×19.6

v

2

=384.16

⇒v=19.6m/s