Question

A stone is released from the top of a water of height 19.6m. Then its final velocity just before touching the ground will be ?​

Answer 1

Explanation:

ANSWER

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v

2

=u

2

+2gs

v

2

=0+2×9.8×19.6

v

2

=384.16

⇒v=19.6m/s

Answer 2

$\huge{\underline{\underline{\sf{\pink{Answer}}}}}$

$Initial \: Velocity \: u=0 \\ </p><p></p><p>Final \: velocity v=? \\ </p><p></p><p>Height, s=19.6m</p><p> \\ </p><p>By \: third \: equation \: of \: motion \\ </p><p>v </p><p>2</p><p> =u </p><p>2</p><p> +2gs \\ </p><p>v </p><p>2</p><p> =0+2×9.8×19.6 \\ </p><p>v </p><p>2</p><p> =384.16 \\ </p><p>⇒v=19.6m/s$

Thus, The answer is 19.6 m/s