Question

a stone is released from the top of the tower of the height 1960 metre calculate the time taken by the stone to hit the ground find the velocity which is hits the ground​in​

Answer 1

Explanation:

to find the velocity of the stone we have 3 equations that are

V=u+at

v² = u² + 2as

s = ut + ½at²

to find velocity by first equation v = u + at.

we don't have t (time)

with 2nd equation

v² = u² + 2as

we know u is 0 and a is gravity that 9.8m/s2

now,

${v}^{2} = 0 + 2 \times 9.8 \times 1960$

=19.6×1960

=38,416

=√38416

=196

therefore, the velocity is 196m/s

now time,

$v = u + gt$

196=0+9.8×t

196=9.8t

196

9.8

=20s

therefore time taken 20sec

velocity-196m/s

time-20s