Question

A stone is released from the top of tower of height 20 m then it's final velocity visit before touching the ground will be (take g=10 m/s^2)​

Answer 1

Answer:

Here is your answer...........!!!!!!!!

Step-by-step explanation:

Given data:

Height of the tower=H= 20m

g= 10 $m s^{-2}$

Solution:

velocity of a body when it reaches the ground= $\sqrt{2gH}$

                                                                             = $\sqrt{2(10)(20)}$

                                                                             = $\sqrt{400}$

                                                                             =  20 m/s

The final velocity of the stone before touching the ground is 20m/s.

I hope my answer is useful to you........!!!!!!!!