Question

A stone is released from the top of tower of height 20 m then it's final velocity just before touching the ground will be (take g =10m/s^2)​

Answer 1

Answer:

20m/s

Explanation:

Using third equation of motion

v^2=u^2+2as

v^2=0+2*10*20

V=20m/s

Answer 2

Answer:

200 m/s

Explanation:

Because a stone released the height 20 m

and g = 10 m/s

= 20m X 10 m

= 200 m/s