Question

A stone is released from the top of tower of height 98 m. Calculate its velocity after 3 seconds

Answer 1

Height if tge tower = 98m

Let assume g = 10m/sec²

Formula for time to taken by reaching the ground=
$= \frac{ \sqrt{2gh} }{}$
T = √2x10x98

T = √1960

T=44

V = u + at..... using newton 1st equation of motion

V = 0 + 10x44

V = 440m/sec

Answer 2

Distance,S = 98m

Time ,t = 3 seconds

Initial velocity,u = 0m/s

Acceleration due to gravity,g = 9.8m/s^2

We know that-

v = u+gt

v = 0+ 9.8*3

v = 29.4m/s