a stone is released from the tower of height 19.6m calculate its final velocity just before touching the ground
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Answered by
0
Hey there !! Here is your answer.....
v(final)= root (2gh)
=root(2*9.8*19.6)
= 19.6 m/s
hope it helps you .
v(final)= root (2gh)
=root(2*9.8*19.6)
= 19.6 m/s
hope it helps you .
Answered by
2
force of gravity pulling the object downwards = 9.8m/s^2.
speed = 19.6 m/s
time =2s
speed = 19.6 m/s
time =2s
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