A stone is released from top of a building of 4.9 calculate time taken by it and the velocity of object at end of 2.5 metre ..
I need WHOLE SUM
(ANSWER : 1sec.,7 METRE PER SECOND
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Given, a=g=10m/s
2
t=4s
u=0m/s {Initial velocity at rest}
So, height= ut+
2
1
at
2
=(0)(u)+
2
1
(10)(16)
=80m
∴ Height of the tower= 80m .
Hope it's help u
Plz thanks on my answers
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