A stone is relesed from the top of a tower of height of 19.6m. Calculate its final velocity just before touching the ground.
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Answer:
Hence, the velocity of the stone just before touching the ground is 19.6 ms^−1.
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Explanation:
given : u = 0, s = 19.6 m, g = 10m/sec²
to find v
formula used: v² - u² = 2gs
=> v² - 0 = 2 * 10 * 19.6
=> v² = 20 * 19.6
=> v² = 392
=> v = √392
=> v = 19.8 m/sec
=> v = w
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