Question

A stone is rotated steadily in a horizontal circle with
a time period T by means of a string of length l. If
the tension in the string is kept constant and length
l increase by 1%, then percentage change in time
period T is-
(A) 1 %
(B) 0.5 %
(C) 2 %
(D) 0.25%​

Answer 1

Answer:0.5%

Explanation:

T=2pie*root(l/g)

dT/T=1/2(dl)/l...... {differentiating above equation of time period}

dT/t*100 is percentage change

Putting all the values

dT/T= 1/2*(1/100)*100

dT/T=0.5%