A stone is suspended from a wire. When the stone is in air and immersed in water, the extensions are in the ratio 9:5. The
specific gravity of the stone is:
1) 3.2
2)1.86
3) 4.48
4) 2.25
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Answer:
specific gravity of the stone is 1.8
Explanation:
let, the extensions of wire in air and water be Δl1 and Δl2
here, Δl1/Δl2 = 9/5
we know, T = 2π √l/g
and T = 1/2 Δl/l
therefore, Δl1/l1 =Δl2/l2
l1/l2=Δl1/Δl2
l1/l2 = 9/5
l1/l2 = 1.8
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