Question

a stone is theown upwards direction with a velocity of 5 ms if acceleeration of the stone during its motion is 10 ms in donward motion is 10 ms in thevdownload direction what will ne the height attended by the stone and how much time will it take to reach there​

Answer 1

max. height = u²/2g

= (5²)/2(10)

= 25/20

= 5/4 m

t (to reach top) = u/g

= 5/10

= 0.5 s

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