Question

a stone is theown upwards direction with a velocity of 5 ms if acceleeration of the stone during its motion is 10 ms in donword motion is 10 ms in thevdownload direction what will ne the height attended by the stone and how much time will it take to reach there​

Answer 1

Answer:

loool

Explanation:

thanks for points

Answer 2

Explanation:

Given, initial velocity, u=5ms−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion. 

∴a=−10ms−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v2−u2=2as, we have

s=v2−u2/2a

=(0)2−(5)2/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s