Question

a stone is throw at an angle of 30° to the horizontal with a velocity 40m/s¹ on a level ground. calculate maximum height reached by the stone & maximum horizontal distance covered by the stone​

Answer 1

Answer:

160 m

Explanation:

From third equation

2as=v^2-u^2

2×10×s=(40)^2-(0)^2

20s=1600

s=80

total displacement=80+80

160m