A stone is throw vertically upward with an inital velocity of 20m/sec.find the maximum height it reached and the time taken by it to reach the height.(g=10m/sec square).
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Given
v= 20 m/s
u=0
a= 10 (because the stone is moving against the gravitational pull)
using newtons equation
v= u+ at
20 = 0 +(10)×t
t= 2 sec
Now again using newtons equation
v2 = u2 + 2as
400=0 + 2×10×s
s= 20 m
v= 20 m/s
u=0
a= 10 (because the stone is moving against the gravitational pull)
using newtons equation
v= u+ at
20 = 0 +(10)×t
t= 2 sec
Now again using newtons equation
v2 = u2 + 2as
400=0 + 2×10×s
s= 20 m
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