Question

A stone is thrown at an angle teta to the horizontal reaches a maximum height 'h' The time of flight of
the stone is
​

Answer 1

Answer:

please make it as brainlist

Answer 2

$\huge\bold\red{anşwέr}$

$\bold{2 \sqrt{ \frac{2H}{g} } }$

$\huge\bold\pink{ѕolutíon }$

$\bold{вч \: uѕíng \: \: \: \: \: s \: = vt - \frac{1}{2} a {2}^{2} }$

$\bold{We \: get \: H = 0 - \frac{1}{2} ( - g)( \frac{T}{2} {)}^{2} }$

$\bold{⇒T = 2 \sqrt{ \frac{2H}{g} } }$

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