Question

A stone is thrown at an angle teta to the horizontal reaches a maximum height h.then the time of flight of stone will be

Answer 1

u²sin²x/2g=h
2usinx/g=?
u²sin²x=2gh
usinx=√2gh
?=2×√2gh/g=2√(2h/g)

Answer 2

A stone is thrown at an angle teta to the horizontal that also reaches a maximum height h then the time of flight of stone will be.

The time of flight is independent of the Maximum height attained as can be seen from the following equation:

U²sin²x/2g=h, 2usinx/g=?, u²sin²x=2gh, usinx=√2gh ?=2×√2gh/g=2√(2h/g).